h^2-17h=-16

Solution for h^2-17h=-16 equation:

h^2-17h=-16

We move all terms to the left:

h^2-17h-(-16)=0

We add all the numbers together, and all the variables

h^2-17h+16=0

a = 1; b = -17; c = +16;
Δ = b2-4ac
Δ = -172-4·1·16
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-15}{2*1}=\frac{2}{2}
=1
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+15}{2*1}=\frac{32}{2}
=16
$